5. Calculate the time required to deposit 0.37g of Silver from a silverNitrate solution using a current of 2.5A( Charge of Ag in AgNO3 is + 1)

Question

asked Sep 23, 2021 167k views

1 Answer

Ivo Welch · Answer 1 · 2021-09-27T18:15:27+0000

Time required : 132.2 s

Given

mass of Silver = 0.37 g

current = 2.5 A

Required

time do deposit

Solution

Faraday's Law :

$\tt W=(e.i.t)/(96500)$

e = ar/valence (valence Ag = 1)

i = current

t = time = s

$\tt 0.37~g=(108/1* 2.5~A* t )/(96500)\\\\t=132.2~s$