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C=2 4 6 3 6 9 4 8 12 find the determinant and inverse of c

User Ahmelq
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1 Answer

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Answer:

The determinant of C is zero and does not have inverse.

Explanation:

Let
C = \left[\begin{array}{ccc}2&4&6\\3&6&9\\4&8&12\end{array}\right], since it is a matrix with 3 rows and 3 columns, we can determine its determinant by the Sarrus' rule:


\det(C) = \left|\begin{array}{ccc}2&4&6\\3&6&9\\4&8&12\end{array}\right|


\det(C) = (2)\cdot (6)\cdot (12)+(3)\cdot (8)\cdot (6)+(4)\cdot (4)\cdot (9)-(4)\cdot (6)\cdot (6)-(3)\cdot (4)\cdot (12)-(2)\cdot (8)\cdot (9)


\det (C) = 0

Since the determinant of C is equal to zero, then we conclude that C does not have an inverse according to the following definition of inverse matrix. That is:


C^(-1) = (1)/(\det(C))\cdot adj(C) (1)

Where
adj(C) is the adjugate matrix of C, defined as the transpose of the cofactor matrix of C.

The result of this expression is undefined due to the determinant.

User Rbento
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