Answer:
The determinant of C is zero and does not have inverse.
Explanation:
Let
, since it is a matrix with 3 rows and 3 columns, we can determine its determinant by the Sarrus' rule:
![\det(C) = \left|\begin{array}{ccc}2&4&6\\3&6&9\\4&8&12\end{array}\right|](https://img.qammunity.org/2021/formulas/mathematics/high-school/ndx15k626qjsglwx6ur8ggbxbtdiyh368e.png)
![\det(C) = (2)\cdot (6)\cdot (12)+(3)\cdot (8)\cdot (6)+(4)\cdot (4)\cdot (9)-(4)\cdot (6)\cdot (6)-(3)\cdot (4)\cdot (12)-(2)\cdot (8)\cdot (9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/xlv361186at8e0xudspoefbq7io86g4x25.png)
![\det (C) = 0](https://img.qammunity.org/2021/formulas/mathematics/high-school/q00uxpx4wsjstq3btpg3gcu949ptulk75z.png)
Since the determinant of C is equal to zero, then we conclude that C does not have an inverse according to the following definition of inverse matrix. That is:
(1)
Where
is the adjugate matrix of C, defined as the transpose of the cofactor matrix of C.
The result of this expression is undefined due to the determinant.