Question

Calculate the pH of a solution that is 0.113 M HCI.

Answer 1

Simplified concentration

`\\ \rm\Rrightarrow 1.13* 10^(-2)M`

Now

`\\ \rm\Rrightarrow pH=-log[H^+]`

`\\ \rm\Rrightarrow pH=-log(1.13* 10^(-2))`

`\\ \rm\Rrightarrow pH=-log1.13-log10^(-2)`

`\\ \rm\Rrightarrow pH=-0.05+2`

`\\ \rm\Rrightarrow pH=1.95`

Highly acidic