Question:
At a sports event, the car starts from rest. in 5.0 s its acceleration is 5.0 m/s2. Calculate the distance travelled by car.
Answer:
62.5 metres
Step-by-step explanation:
Given
-- Initial Velocity
--- acceleration
-- time
Required
Calculate the distance
This question will be solved using the following equation of motion
![S = ut + (1)/(2)at^2](https://img.qammunity.org/2021/formulas/physics/college/1nwapli3qmf9lu0tlcpbu5z9m01nsc1a6w.png)
Where S represents the distance
Substitute values for u, t and a
![S = 0 * 5.0 + (1)/(2) * 5.0 * 5.0^2](https://img.qammunity.org/2021/formulas/physics/high-school/xo2kvwt1q2pbs1xbe1h0nmz6co3fd4e8jo.png)
![S = 0 + (1)/(2) * 5.0 * 25.0](https://img.qammunity.org/2021/formulas/physics/high-school/f23rqrhwuzzuras977myv67y5vxg7xa2oo.png)
![S = (1)/(2) * 5.0 * 25.0](https://img.qammunity.org/2021/formulas/physics/high-school/bl6lp7ff1pwmxt7qcnumhn0m7sz86fgp86.png)
![S = (1)/(2) * 125.0](https://img.qammunity.org/2021/formulas/physics/high-school/172zfblwj22mjfi46txxlcnw664lub2zfv.png)
![S = 62.5m](https://img.qammunity.org/2021/formulas/physics/high-school/o2nsq5gicrsmli0oph749xh55d9myenqal.png)
Hence, the distance travelled is 62.5m