Question

Help pls its been a day

Answer 1

The sum of the two vectors is 161.278 m.

Step-by-step explanation:

Given;

vector, B = 101 m inclined at angle 60⁰

vector, A = 85 m inclined at angle 0⁰

Y-component of the vectors;

`R_y = 101(sin \ 60^0) + 85(sin \ 0^0) =87.466 \ m`

X-component of the vectors;

`R_x = 101(cos \ 60^0) + 85(cos \ 0^0)\\\\R_x = 50.5 + 85 = 135.5 \ m`

Sum of the two vectors;

`R = A+ B\\\\R = √(R_y^2 + R_x^2) \\\\R = √(87.466^2 \ + \ 135.5^2) \\\\R = √(26010.55) \\\\R = 161.278 \ m`

Therefore, the sum of the two vectors is 161.278 m.

Answer 2

161.28m

Step-by-step explanation:

The resultant is calculated using the formula

R² = dx²+dy²

R = √dx²+dy²

From the diagram. dx = 101cos60°+85

dx = 101(0.5) + 65

dx = 50.5 + 85

dx = 135.5m

For the vertical component dy

dy = dsin theta

dy = 101 sin 60

dy = 101(0.8660)

dy = 87.47

R = √135.5²+87.47²

R = √18,360.25+7,651.0009

R = √26,011.2509

R = 161.28m

Hence the magnitude of the sum of the vectors is 161.28m