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How many grams of glucose (C6H12O6) are contained in 555 mL of a 1.77 M glucose solution?
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Aug 16, 2023
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How many grams of glucose (C6H12O6) are contained in 555 mL of a 1.77 M glucose solution?
Chemistry
college
Afeshia
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molarity =wt/M.wt * 1000/V
=> 1.77 = wt/180 * 1000/555
> wt = 1.77 * 180*555 /1000 = 176.823 g
Adamdboudreau
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Aug 22, 2023
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