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What is the ph of a peach with a [ –oh] = 3.2 × 10 –11 m?
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What is the ph of a peach with a [ –oh] = 3.2 × 10 –11 m?

User Ellickakudy Rajeesh
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H+= 10^-14 / [OH-1 = 3.125 * 10^-4 M
pH=-log(H+) = 3.505

Just round it down and your answer = 3.5
User Dhaval Purohit
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