Final answer:
The correct statement is ΔADB ≅ ΔADC, using the SSS Triangle Congruence Postulate, as AD is a common side, and we have BD = DC and AB = AC in the isosceles triangle.
Step-by-step explanation:
The question pertains to identifying the correct statement about isosceles triangle congruence in an isosceles triangle ABC, where angles B and C are congruent, and BC is bisected at D with AD drawn. By the Side-Side-Side (SSS Triangle Congruence Postulate), which states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent, the correct statement is ΔADB ≅ ΔADC. This is because AD is a common side in both triangles ADB and ADC, BD = DC as D is the midpoint of BC, and AB = AC by the definition of an isosceles triangle where two sides are equal.
To further clarify, in triangle ADB, sides AD, DB, and AB are congruent to AD, DC, and AC respectively in triangle ADC.