Answer:
The initial value = 2
Hence, option (d) is true.
Explanation:
Consider the function
f(x) = abˣ
Given the points
substituting (1, 6) in the function
y = abˣ
6 = ab¹
6 = ab
substituting (2, 18) in the function
y = abˣ
18 = ab²
18 = ab×b
18 = 6×b ∵ ab = 6
b = 18/6
b = 3
now substituting b = 3 in 6 = ab
6 = ab
6 = a × 3
a = 6/3
a = 2
In order to determine the initial value, we need to put x = 0 in the function
y = abˣ
putting x = 0
y = ab⁰
as a = 2 and b⁰=1
so substituting a = 2 and b⁰=1
y = 2×1
y = 2
Therefore, the initial value = 2
Hence, option (d) is true.