Question

A stone is thrown vertically upward with a speed of 14.6 m/s from the edge of a cliff 93 m high. What total distance did it travel

Answer 1

The value is
`H = 114.74 \ m`

Step-by-step explanation:

From the question we are told that

The initial speed is
`u = 14.6 \ m/s`

The height of the cliff is
`h_o = 93 \ m`

Generally from kinematic equation we have that

`v^2 = u^2 + 2as`

At maximum height , v which is the finial velocity is zero

So

`0^2 = 14.6^2 + 2 * (- 9.8) * s`

=>
`s = 10.87 \ m`

Generally the total distance traveled is mathematically represented as

`H = 2 * s + h_o`

=>
`H = 2 * 10.87 + 93`

=>
`H = 114.74 \ m`