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A 23.0 kg child is riding a playground merry-go-round that is rotating at 30.0 rpm. What centripetal force, in N, must she exert to stay on if she is 2.00 m from its center

1 Answer

3 votes

Answer:

The value is
F = 454 \ N

Step-by-step explanation:

From the question we are told that

The mass of the child is
m = 23.0 \ kg

The angular velocity is
w = 30 \ rpm = (2 \pi * 30 )/(60) = 3.142 \ rad/s

The distance from the center is
r = 2.0 \ m

Generally the centripetal force is mathematically represented as


F = m * w^2 * r

=>
F = 23 * 3.142 ^2 * 2

=>
F = 454 \ N

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