Question

You have a vinegar solution you believe to be 0.73 M. You are going to titrate 20.99 mL of it with a NaOH solution that you know to be 0.583 M. At what volume of added NaOH solution would you expect to see an end point

Answer 1

The answer is "262.83 mL"

Step-by-step explanation:

The equation for the reaction is :

`HA+ NaOH \longrightarrow NaA+H_2 O`

a)

Calculating the moles of HA:

`=0.02099 \ LHA * (0.73 \ mol \ HA)/(1 \ L HA)\\\\= 0.153227 \ mol HA`

b)

Calculating the moles of NaOH:

`= 0.153227 \ mol \ HA * (1 \ mol\ NaOH)/(1 \ mol \ HA)\\\\ = 0.153227\ mol \ NaOH`

c)

Calculating the volume of the NaOH:

`=0.153227 \ mol \ NaOH * (1 \ L \ NaOH)/(0.583 \ mol \ NaOH)\\\\= 0.262825043\ L \\\\ = 262.83 \ mL`