3i(4 - I) + i(6 + 2i) - QAmmunity.org

asked Oct 24, 2021 182k views

1 vote

3i(4 - I) + i(6 + 2i)

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7 votes

Answer:

-1 + 18i

Explanation:

⟺ Distribute 3i and i in the expressions.

$12i-i^2+6i+2i^2\\i^2+18i$

⟺ The define of complex number is

i^2=-1

Thus, convert i² to -1

-1+18i

Phil Gyford answered Oct 31, 2021

6.2k points

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