86.3k views
3 votes
a copper wire has a square cross section 2.0 mm on a side.it is 4m connected to a power supply of 10v,the resistivity of copper is 1.7*10^-8 Ω what is the current density

1 Answer

3 votes

Answer:

1.47·10^8 A/m^2

Step-by-step explanation:

The current density is ...

J = E/(ρ·L) = 10 V/((1.7·10^-8 Ω·m^2/m)(4 m)) = 1.47·10^8 A/m^2

User Knut Haugen
by
6.1k points