Question

Caluclate the volume of0,25 mol dm -^3 hydrochloric acid required to neutralize 2.0 dm^3 of 0,15 mol dm-^3 barium hydroxide

Answer 1

d

Step-by-step explanation:

d

Answer 2

2.4 dm-3

Step-by-step explanation:

Equation of the reaction;

2HCl(aq) + Ba(OH)2(aq) -------> BaCl2(aq) + 2 H2O(l)

Volume of acid VA = ??

Concentration of acid CA = 0.25 moldm-3

Volume of base VB = 2.0 dm^3

Concentration of base CB = 0.15 moldm-3

Number of moles of acid NA = 2

Number of moles of base NB = 1

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

VA = CBVBNA/CANB

VA = 0.15 * 2 * 2/0.25 *1

VA = 2.4 dm-3