Question

Calculate the drop voltage for a battery of internal resistance 2 ohm and emf of 24 volt

When connected to external resistance of 158 ohm.

Answer 1

The drop voltage is 0.3 V

Step-by-step explanation:

Electromotive Force EMF

When connecting a battery of internal resistance Ri and EMF ε to an external resistance Re, the current through the circuit is:

`\displaystyle i=(\varepsilon )/(R_e+R_i)`

The battery has an internal resistance of Ro=2 Ω, ε=24 V and is connected to an external resistance of Re=158 Ω. Thus, the current is:

`\displaystyle i=(24 )/(158+2)`

`\displaystyle i=(24 )/(160)`

i = 0.15 A

The drop voltage is the voltage of the internal resistance:

`V_i = i.R_i`

`V_i = 0.15*2`

`\boxed{V_i = 0.3\ V}`

The drop voltage is 0.3 V