Question

If the temperature is held constant during this process and the final pressure is 671 torr , what is the volume of the bulb that was originally filled with gas

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

Step-by-step explanation:

From the question we are told that

The initial pressure of the gas is
`P_1 = 1.50 \ atm`

The volume of the second bulb is
`V_2 = 0.800 \ L`

The final pressure of the gas is
`P_2 = 671 \ torr = (671 )/( 760) = 0.883 \ atm`

Let the unknown volume be represented as
`V_1 = V \ L`

Generally from Boyle's law we have that

`P_1 * V_1 = P_2 * V_2`

=>
`1.50 * V = 0.883 * 0.800`

=>
`V = 0.479 \ L`