Question

The potential at location A is 570 V. A positively charged particle is released there from rest and arrives at location B with a speed vB. The potential at location C is 1180 V, and when released from rest from this spot, the particle arrives at B with twice the speed it previously had, or 2 vB. Find the potential at B.

Answer 1

Potential at B, VB = 367 V

Step-by-step explanation:

The explanation is found in the attachment below