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The potential at location A is 570 V. A positively charged particle is released there from rest and arrives at location B with a speed vB. The potential at location C is 1180 V, and when released from rest from this spot, the particle arrives at B with twice the speed it previously had, or 2 vB. Find the potential at B.

User Aopsfan
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1 Answer

6 votes

Answer:

Potential at B, VB = 367 V

Step-by-step explanation:

The explanation is found in the attachment below

The potential at location A is 570 V. A positively charged particle is released there-example-1