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A spacecraft at rest has moment of inertia of 100 kg-m^2 about an axis of interest. If a 1 newton thruster with a 1 meter moment arm is fired orthogonal to the axis of interest for 1 minute, how far has the vehicle rotated when the firing is complete?

User Vectorizor
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1 Answer

5 votes

Answer:

18 radians

Step-by-step explanation:

The computation is shown below:

As we know that

Torque = Force × Moment arm

= 1N × 1M

= 1N-M

Torque =
I\alpha


\alpha = (torque)/(I)\\\\= (1)/(100)\\\\= 0.01 rad/s^2

Now


\theta = w_ot + (1)/(2) \alpha t^2\\\\w_o = 0\\\\\theta = 0 * 60 + (1)/(2) * 0.01 * 60^2\\\\= 18\ radians

Here t = 1 minutes = 60 seconds

User Yuriy Gavrishov
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