Question

create your own min function that finds the minimum element in a list and use it in a separate function

Answer 1

def minfunction(mylist):

min = mylist[0]

for i in mylist:

if i < min:

min = i

print("The minimum is: "+str(min))

def anotherfunction():

mylist = []

n = int(input("Length of list: "))

for i in range(n):

listelement = int(input(": "))

mylist.append(listelement)

minfunction(mylist)

anotherfunction()

Step-by-step explanation:

This solution is implemented in Python

This defines the min function

def minfunction(mylist):

This initializes the minimum element to the first index element

min = mylist[0]

This iterates through the list

for i in mylist:

This checks for the minimum

if i < min:

... and assigns the minimum to variable min

min = i

This prints the minimum element

print("The minimum is: "+str(min))

This defines a separate function. This separate function is used to input items into the list

def anotherfunction():

This defines an empty list

mylist = []

This prompts user for length of list

n = int(input("Length of list: "))

The following iteration inputs elements into the list

for i in range(n):

listelement = int(input(": "))

mylist.append(listelement)

This calls the minimum function

minfunction(mylist)

The main starts here and this calls the separate function

anotherfunction()