Answer:
x = 150°
Explanation:
The given parameters are;
AB ║ DC
∠BAE = 105°
∠AEC = 25°
We construct a line CF from C parallel to the line AE as presented in the included diagram created with Microsoft Visio
We have;
∠DCF ≅ ∠BAE = 105° by similar angles formed by two pairs of parallel lines
∠AEC = ∠ECF = 25° by alternate interior angles formed by two parallel lines and a common transversal
x = 125° + 25° = 150° By angle addition postulate
x = 150°.