Answer:
10
Explanation:
Given that:
Total number of students = 50
Students who like to play football = 25
![n(A) = 25](https://img.qammunity.org/2021/formulas/mathematics/high-school/56rp4zz8zw1l39pzg32me8ahayit5q1mj2.png)
Students who like to play cricket = 35
![n(B) = 35](https://img.qammunity.org/2021/formulas/mathematics/high-school/dkc6qhcmjkemksvfyfrmy3o90qn0ya6oax.png)
Each student likes to play at least one game.
It means the universal set is equal to the union of the above two sets.
![n(U) =n(A\cup B) = 50](https://img.qammunity.org/2021/formulas/mathematics/high-school/ixv4m48diuanfayagp0uklr6vgwgepckqy.png)
To find:
The number of students who play both the games and representation of the given situation in the form of a Venn diagram.
i.e.
![n(A\cap B) = ?](https://img.qammunity.org/2021/formulas/mathematics/high-school/ed2xzvyx3vj8a5vvx3y05tgvl49ys17vcy.png)
Solution:
First of all, let us have a look at the formula for the number of elements in the union of two sets.
![n(A\cup B)=n(A)+n(B)-n(A\cap B)](https://img.qammunity.org/2021/formulas/mathematics/college/jqxivvug4rjo8lmldyo4h2mjtnz0ldp80r.png)
Putting the values in the formula, we need to find the value of
![n(A\cap B)](https://img.qammunity.org/2021/formulas/mathematics/high-school/iieme8ddwjjxxlwftlqazdf1cdvx7nw709.png)
![50=25+35-n(A\cap B)\\\Rightarrow 50-60=-n(A\cap B)\\\Rightarrow n(A\cap B)=\bold{10}](https://img.qammunity.org/2021/formulas/mathematics/high-school/zw8c8xg5kp7b68gx811fvvjfmgj3ev1s5h.png)
Therefore, the number of students who like to play both the games is 10.