Question

If 8.00 mol of NH3 reacted with 14.0 mol of O2, how many moles of H20 will be produced?

4NH3(g) + 702(g) → 4NO2 + 6H2O(g)

Answer 1

To find the number of moles of H₂O produced when 8.00 mol of NH₃ reacts with 14.0 mol of O₂, we can use the balanced chemical equation and the mole ratio between NH₃ and H₂O.

Step-by-step explanation:

To find the number of moles of H₂O produced when 8.00 mol of NH₃ reacts with 14.0 mol of O₂, we need to use the balanced chemical equation and the mole ratio between NH₃ and H₂O. From the equation, we see that for every 4 moles of NH₃, 6 moles of H₂O are produced. This means that for 8.00 mol of NH₃, we would produce:

8.00 mol NH₃ x (6 mol H₂O/4 mol NH₃) = 12.0 mol H₂O

Therefore, 12.0 moles of H₂O will be produced.