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100 POINTS!!!! PLZ HELP ME, I AM AN IDIOT!

In the figure, k>0.

(a) Is ΔABC similar to ΔPQR? Support your answer with a theorem or postulate.

(b) How does the area of ΔPQR compare tot he area of ΔABC? Justify your answer.

100 POINTS!!!! PLZ HELP ME, I AM AN IDIOT! In the figure, k>0. (a) Is ΔABC similar-example-1
User Ekchang
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2 Answers

2 votes

Answer and Step-by-step explanation:

For question A)

ABC is similar to PQR because of the AA similarity postulate. This postulate states that if any two angles in a triangle are congruent to the other two angles in a triangle, then the triangles are similar.

For question B)

The area would be k times more than the area of ABC.

The area of a triangle is bh/2, or base times height, divided by 2.

And since they both have 4, the one with the k will be k times greater.

Hopefully this helps!!

#teamtrees #WAP (Water And Plant)

User Morpheus
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6 votes

Answer:

  • (a) yes
  • (b) Area of ΔPQR is k² times greater

Explanation:

(a) As per the diagram, the triangles are similar.

  • ∠B ≅ ∠Q and ∠C ≅ ∠R

ΔABC ~ ΔPQR as per AA similarity postulate (two congruent angles)

(b) The area is the product of two dimensions. Area of ΔABC

  • A = 1/2bh

Since each side of ΔPQR is k times greater than corresponding sides of ΔABC, the base and height will be both k times greater.

So the area of ΔPQR will be:

  • A = 1/2bkhk = 1/2bh*k²

The area of PQR is k² times greater than the area of ΔABC

User Ismnoiet
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5.7k points