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Calculate the magnitude and direction of the centripetal acceleration of the following objects moving in a circle:

A 2000 kg truck drives along a circular round a bout with a radius of 20 m at a constant speed of 10 m/s.

User Ibab
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1 Answer

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Answer:

The magnitude and direction of the centripetal acceleration will be:


a_c=5 m/s² (towards the center of the circle).

Step-by-step explanation:

Given

  • v = 10 m/s
  • r = 20 m

Using the formula to determine the centripetal acceleration


a_c=(v^2)/(r)


a_c=(\left(10\right)^2)/(20)


\:a_c=(100)/(20)


a_c=5 m/s²

As the truck is moving in a circle, therefore the direction is towards the center of the circle.

Hence, the magnitude and direction of the centripetal acceleration will be:


a_c=5 m/s² (towards the center of the circle).

User Temirbek
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