Explanation:
Hey there!
The given equation of line PQ is :
y = -3x -12.
Comparing the equation with y = mx + c. We get;Slope (m1)= -3
We know the condition of parallel lines is slope of 1st line = slope of 2nd line. (i.e m1=m2).
Therefore, slope of PQ= slope of ST = -3.
Now, The point through which ST passes is (3,-1) and we found its slope as -3.
So, let's use one point formula.
![(y - y1) = m2(x - x1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/gv4b2nkszpoob8fkg8wewtkxxms0l1mxir.png)
![(y + 1) = - 3(x - 3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/le1dpbiy5f3ixc5tqjzqkt307ugdy2uccp.png)
![y + 1 = - 3x + 9](https://img.qammunity.org/2021/formulas/mathematics/high-school/bciy8jn1ak5buibo9xsvioj4mltmi3dsc5.png)
![y = - 3x + 8](https://img.qammunity.org/2021/formulas/mathematics/high-school/5qdiugy1gbxasdf9h31k8rza8salbninzx.png)
Comparing the equation with y = mx+c. We get y-intercept is "8".
Therefore, y-intercept is "8".