Question

how many grams of zinc will be formed if 32 G of copper reacts with zinc nitrate copper 1 nitrate is the other product ​

Answer 1

Mass = 32.69 g

Step-by-step explanation:

Given data:

Mass of copper = 32 g

Mass of zinc formed = ?

Solution:

Chemical equation:

Cu + Zn(NO₃)₂ → Cu(NO₃)₂ + Zn

Number of moles of copper:

Number of moles = mass/molar mass

Number of moles = 32 g/ 63.55 g/mol

Number of moles = 0.5 mol

now we will compare the moles of zinc with copper.

Cu : Zn

1 : 1

0.5 : 0.5

Mass of Zn:

Mass = number of moles × molar mass

Mass = 0.5 mol × 65.38 g/mol

Mass = 32.69 g