Answer:
10080, 10290
Explanation:
The multipliers of 210 required will be mutually prime integers that satisfy ...
10000 ≤ 210n ≤ 11000
47.61 ≤ n ≤ 52.38
That is, you want a pair of integers, each between 48 and 52, that have no common factors. Possibilities include ...
(48, 49), (49, 50), (49, 51), (49, 52), (50, 51), (51, 52)
For the above numbers, we have chosen ...
48×210 = 10,080
49×210 = 10,290