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Prove that : 1/1-secA + 1/1+secA = -2cot^2A​

Prove that : 1/1-secA + 1/1+secA = -2cot^2A​
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Prove that : 1/1-secA + 1/1+secA = -2cot^2A​

User Mtekeli
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1 Answer

5 votes

Answer:

Explanation:

LHS = 1/1-secA + 1/1+secA


= (1*(1+Sec A))/((1-Sec A)(1+Sec A))+(1*(1-Sec A))/((1+Sec A)*(1-Sec A))\\\\=((1+Sec A))/(1-Sec^(2) A)+((1-Sec A))/(1-Sec^(2) A)\\\\=(1+Sec A+1-Sec A)/((1-Sec^(2) A))\\\\= (2)/((1-Sec^(2) A))\\\\=(2)/(-(Sec^(2) A - 1))\\\\= (-2)/(Tan^(2) A)\\\\= -2Cot^(2) A

Prove that : 1/1-secA + 1/1+secA = -2cot^2A​-example-1
User Pellay
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