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Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA​

User Gozwei
by
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1 Answer

3 votes

Explanation:


(sinA)/(1+cosA) +(1+cos)/(sinA) =2cosec\\\\\\(sin^(2)A+(1+cos)^(2) )/(sinA(1+cosA)) \\\\


(sin^(2)A+1+cos^(2)+2cos)/(sinA(1+cosA)) \\\\ and we have
sin^(2)+cos^(2) =1

so
(1+1+2cosA )/(sinA(1+cosA)) \\\\


(2+2cosA )/(sinA(1+cosA)) \\\\


(2(1+cosA))/(sinA(1+cosA)) \\\\


(2)/(sinA) we have
(1)/(sin)=cosec\\

Finally
2cosecA

I really hope this helps coz it took much time

User Jon Portella
by
7.7k points

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