Question

Pls PLS solve T_T i tried everything ​

Answer 1

Let AO intersect BC at D

ΔAOB = ΔBOC = ΔAOC (SAS)

AB = BC = AC

ΔABC is equilateral

O is the circumcenter of equilateral ΔABC

Therefore, O is also the centroid of ΔABC

AO / AD = 2/3

2
`√(3)` / AD = 2/3

AD = 3
`√(3)`

Right triangle ADB has ∠ABD = 60°

AB / AD = 2/
`√(3)`

AB / 3
`√(3)` = 2/
`√(3)`

AB = 6

Perimeter of ΔABC = 6 + 6 + 6 =18

Answer 2

12√3 is the correct answer