Answer:
16 The value by which (8x^2 - 9y^2)(8x
2
−9y
2
) is larger than (3x^2 - 2y^2)(3x
2
−2y
2
) is as follows:-
\begin{gathered}(8x^2 - 9y^2) - (3x^2 - 2y^2)\\= 8x^2 - 9y^2 - 3x^2 + 2y^2\\= 5x^2 -7y^2\end{gathered}
(8x
2
−9y
2
)−(3x
2
−2y
2
)
=8x
2
−9y
2
−3x
2
+2y
2
=5x
2
−7y
2