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Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunnel syndrome (CTS). An article reported on a test that involved sensing a tiny gap in an otherwise smooth surface by probing with a finger; this functionally resembles many work-related tactile activities, such as detecting scratches or surface defects. When finger probing was not allowed, the sample average gap detection threshold for m = 5 normal subjects was 1.76 mm, and the sample standard deviation was 0.55; for n = 11 CTS subjects, the sample mean and sample standard deviation were 2.56 and 0.84, respectively. Does this data suggest that the true average gap detection threshold for CTS subjects exceeds that for normal subjects? State and test the relevant hypotheses using a significance level of 0.01. (Use μ1 for normal subjects and μ2 for CTS subjects.)

Required:
Calculate the test statistic and determine the P-value.

User Dstarh
by
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1 Answer

5 votes

Answer

test statistic
t = -2.27

P-value
p- value = 0.0198

Explanation:

From the question we are told that

The first sample size is
n_1 = 5

The first sample mean is
\= x_1 = 1.76 \ mm

The first standard is
s_1 = 0.55

The second is
sample \ size\ is\ n_2 = 11

The second sample mean is
\= x_2 = 2.56

The second standard deviation is
\sigma = 0.84

The level of significance is
\alpha = 0.01

The null hypothesis is
H_o : \mu_1 - \mu_2 = 0

The alternative hypothesis is
H_a: \mu_1 - \mu_2 < 0

Generally the test statistics is mathematically represented as


t = \frac{ (\= x _1 - \= x_2) - ( \mu_1 - \mu_2)}{ \sqrt{(s_1 ^2 )/( n_1 ) + (s_1 ^2 )/( n_1 ) } }

=>
t = \frac{ (1.76 - 2.56 ) - 0 }{ \sqrt{(0.55^2 )/( 5 ) + (0.84^2 )/(11 ) } }

=>
t = -2.27

Generally degree of freedom is mathematically represented as


df = n_1 + n_2 - 2

=>
df = 5 + 11 - 2

=>
df = 14

From the student t distribution table the probability value to the left that corresponds to
t = -2.27 at a degree of freedom of
df = 14 is


p- value = 0.0198

User Michael Xin Sun
by
5.2k points
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