Answer:
t = 3.156
Explanation:
N = 9
Please check attachment for the table
ED = 89
ED² = 1587
Bar D = 89/9
= 9.8889
The standard deviation s
= √14283-7921/81
= √78.5432
S = 8.8625
The test statistic
= 9.8889/8.8625/√9-1
= 9.8889/3.1334
= 3.156
From the calculations above, the calculated test statistic t is = 3.156.
Please check the attachment for a more detailed solution to this problem.
Thank you!