Question

The yeast Schizosaccharomyces pombe activates transcription of certain genes in the presence of cAMP. To identify a consensus sequence that responds to cAMP activation, you compare the DNA sequences of 10 different promoters that are activated by cAMP-responsive transcription factors, focusing on the regions of the promoters between nucleotides at positions -100 to -86, where 1 is the first nucleotide copied in the mRNA transcript. From the following data, suggest a consensus sequence responsible for cAMP activation of promoters in this organism. Briefly explain the reason(s) for your choices.

5' 100 -90
A 4 2 1 3 1 0 10 0 1 0 5 2 3
T 0 10 0 1 0 5 2 3 2 1 3 1 0
C 10 1 3 1 0 10 0 1 0 5 2 3 6
G 4 2 1 3 1 0 10 5 2 3 2 1 3

Answer 1

Following are the solution to this question:

Step-by-step explanation:

Consider its nucleotide that many of the time arrives to suggest a binding site. For example, nucleic acid A comes four hours at the place-100th, mostly on the list. Consequently, A would be the -100th nucleic acid. The following was its pattern:

`\to AC/GTY/TTGACGTRT/CAGG`

`\to R = \ any \ pure \\\\\to Y = \ any \ pyrimidine\\\\ \to (a)/(b) = either \ a \ or \ b`