Question

Combined resistance of two resistors connected in parallel is 6Ω. One of the resistance is 12Ω . What will be the resistance of the second resistor?

Answer 1

Step-by-step explanation:

Combined resistance = 1 / [1/12 + 1/x] = 6

1/12 + 1/x = 1/6

x = 12

The resistance of the 2nd resistor is 12Ω.