Question

Someone please help its really important i don’t have much time left. How much energy would be absorbed as heat by 75g of iron when heated from 295k to 301k note that the specific heat of iron is 0.449j/g.k

Answer 1

Q = 202.05 J

Step-by-step explanation:

Given data:

Mass of iron = 75 g

Initial temperature = 295 K

Final temperature = 301 K

Specific heat capacity of iron = 0.449 J/g.K

Heat required = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 301 K - 295 K

ΔT = 6K

Q = 75 g ×0.449 J/g.K × 6K

Q = 202.05 J