Question

Please help!-- 20 pts!

The electrolyte lithium chloride (LiCl) dissolves into positively charged Li+ and negatively charged Cl– ions in water containing electrodes.

What will happen next?

The positively charged ions will be attracted to the negative electrode and gain electrons. Meanwhile, the negatively charged ions will be attracted to the positive electrode and release electrons.
The negatively charged ions will be attracted to the negative electrode and release electrons. Meanwhile, the positively charged ions will be attracted to the positive electrode and gain electrons.
The positively charged ions will be attracted to the negative electrode and release electrons. Meanwhile, the negatively charged ions will be attracted to the positive electrode and gain electrons.
The negatively charged ions will be attracted to the negative electrode and gain electrons. Meanwhile, the positively charged ions will be attracted to the positive electrode and release electrons.

Answer 1

The positively charged ions will be attracted to the negative electrode and gain electrons. Meanwhile, the negatively charged ions will be attracted to the positive electrode and release electrons.

Step-by-step explanation:

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Answer 2

Answer: The positively charged ions will be attracted to the negative electrode and gain electrons. Meanwhile, the negatively charged ions will be attracted to the positive electrode and release electrons.

Step-by-step explanation:

Electrolysis is breaking down of a substance into its constituents by the action of electrical current.

`LiCl\rightarrow Li^++Cl^-`

Cations wich are positively charged specie moves towards the negatively charged electrode that is towards the cathode. On reaching cathode, cations accepts electrons and get reduced through reduction reaction.

`Li^++e^-\rightarrow Li`

Anions wich are negatively charged specie moves towards the positively charged electrode that is towards the anode. On reaching anode, anions donate electrons and get oxidized through oxidation reaction.

`Cl^-\rightarrow Cl+e^-`