Question

A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 110,000 kg of scrap metal into it. (a) What is the final velocity of the loaded freight car? (b) How much kinetic energy is lost?(Check 2 choices for the answer) *

Answer 1

Step-by-step explanation:

Given that,

Mass of a freight car,
`m_1=30,000-kg`

Speed of a freight car,
`u_1=0.85\ m/s`

Mass of a scrap metal,
`m_2=110,000\ kg`

(a) Let us assume that the final velocity of the loaded freight car is V. The momentum of the system will remain conserved as follows :

`30000* 0.85=(30000+110000)V\\\\V=(30000* 0.85)/(30000+110000)\\\\=0.182\ m/s`

So, the final velocity of the loaded freight car is 0.182 m/s.

(b) Lost on kinetic energy = final kinetic energy - initial kinetic energy

`\Delta K=(1)/(2)[(m_1+m_2)V^2-m_1u_1^2)]\\\\=(1)/(2)* [(30,000+110,000 )0.182^2-30000(0.85)^2]\\\\=-8518.82\ J`

Lost in kinetic energy is 8518.82. Negative sign shows loss.