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Write an euqation of a line that is perpendicular to y=1/2x+3 and passes through the point (10,-5)

User Ha Dang
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1 Answer

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Explanation:

Slope of the perpendicular line = (-1)/(1/2) = -2.

y = -2x + c. When x = 10, y = -5.

=> (-5) = -2(10) + c, c = 15.

Hence the equation of the line is y = -2x + 15.

User Nareddyt
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