Question

A bag contains 10 balls of which 6 are red and the rest white and blue of equal numbers. If a ball is picked at random, find the probability that it is either white or red.

Answer 1

`(4)/(5)`

Explanation:

Let
`w` = number of white balls,
`b` = number of blue balls

6 +
`w` +
`b` = 10

`w` +
`b` = 4

`\because`
`w` =
`b`

`\therefore`
`w` +
`b` =

`w` =
`2`

`P`(
`r`∪
`w`) =
`P(r) + P(w) - P(r`∩
`w)`

=
`(6)/(10) + (2)/(10) - (0)/(10)`

=
`(8)/(10)`

=
`(4)/(5)`

`\therefore` The probability of picking either a red or white ball is
`(4)/(5)`

Hope this helps :)

Answer 2

Since each ball has an equal chance of being drawn: 16 p = 1, or ... You can either apply the first equation to find that. B = 1 - R = 3/8 ... A box contains 5 white, 6 red, and 4 black balls of identical size. If 3 balls are ... What is the probability of getting 2 red balls if we pick 3 balls from the bag randomly

Explanation: