Question

3. The equation for the decomposition of sodium hydrogencarbonate is :

2 NaHCO3 (s) → Na2CO3 (s) + H2O(l) + CO2(8)
If 21 g of sodium hydrogencarbonate were decomposed, calculate
(a) the mass of the residue formed.
(b) the volume of carbon dioxide evolved measured at r.t.p.​

Answer 1

a. 13.25 g

b. 3 L

Further explanation

Given

21 g of Sodium hydrogencarbonate

Reaction

2 NaHCO3 (s) → Na2CO3 (s) + H2O(l) + CO2(g)

Required

mass of residue

volume of CO2

Solution

mol NaHCO₃ (MW=84 g/mol) :

`\tt mol=(21)/(84)=0.25`

a. the residue = Na₂CO₃

From the equation, mol ratio NaHCO₃ : Na₂CO₃ = 2 : 1, so mol Na₂CO₃ :

`\tt (1)/(2)* 0.25=0.125`

mass Na₂CO₃ (MW=106 g/mol) :

`\tt mass=0.125* 106=13.25~g`

b. From equation, mol CO₂ = 0.5 x mol NaHCO₃ = 0.125

RTP= 25 C, 1 atm ⇒ 1 mol =24 L

So volume CO₂ :

`\tt 0.125* 24=3~L`