Question

An ice skater is gliding horizontally across the ice with an initial velocity of 7.56 m/s. The coefficient of kinetic friction between the ice and the skate blades is 0.0695, and air resistance is negligible. How much time elapses before her velocity is reduced to 2.32 m/s

Answer 1

Answer: 7.723s

Step-by-step explanation:

given data:

initial velocity = 7.56 m/s.

friction = 0.0695.

change in velocity = 2.32 m/s

Solution:

`ax = (-Fk)/(m)`

`ax = (-ukFN)/(m)`

`ax = (-ukmg)/(m)`

`ax = -ukg`

`recall = v0x +axt`
`.......eqn1`

`t = (vx - v0x)/(ax)`
`........eqn2`

`substitute`
`ax`
`into`
`eqn 2`

`t = (vx -v0x)/(-ukg)`

`t = (2.32m/s - 7.56m/s)/(-(0.0695)(9.80m/s^(2)))`

`t= 7.723seconds`