Question

An open milk carton is pierced by an ice pick 12 cm below the surface of the liquid. Calculate the speed at which milk exits through the resulting hole. [Hint: Be careful with units!]

Answer 1

v = 1.54 m/s.

Step-by-step explanation:

Given that,

An open milk carton is pierced by an ice pick 12 cm below the surface of the liquid.

We need to find the speed at which milk exists through the resulting hole.

Let the speed is v. We can find it using the third equation of motion as follows :

`v^2-u^2=2gs`

u = 0

`v^2=2gs\\\\v=√(2gs) \\\\=√(2* 10* 0.12) \\\\=1.54\ m/s`

So, milk exists through the resulting hole is 1.54 m/s.