Answer:
The theoretical yield of H₂O from 18 g of H₂ is approximately 160.88 g
Step-by-step explanation:
The given chemical equation of the reaction is given as follows;
2H₂ (g) + O₂ (g) → 2H₂O (l)
The mass of the H₂O produced = 130 g
The mass of H₂ in the reaction = 18 g
Therefore, we have;
Two moles of hydrogen gas, H₂ is added to one mole of oxygen gas, O₂ will produce two moles of water, H₂O
The molar mass of H₂O = 18.01528 g/mol
The molar mass of O₂ = 32 g/mol
The molar mass of H₂ = 2.016 g/mol
The number of moles. n is given by, n = (The mass)/(The molar mass)
The number of moles of H₂ in the reaction = 18 g/(2.016 g/mol) ≈ 8.93 moles
The number of moles of H₂O produced (actual yield) = 130 g/(18.01528 g/mol) ≈ 7.216 moles
Therefore, given that 2 moles of H₂ produces 2 moles of H₂O, the expected (theoretical) yield of H₂O from 8.93 moles of H₂ is 8.93 moles of H₂O.
The mass of the theoretical yield of H₂O = 8.93 moles × 18.01528 g/mol = 160.8645 grams ≈ 160.88 grams
The theoretical yield of H₂O from 18 grams of H₂ ≈ 160.88 grams