Question

A vertical tube 1.34 m long is open at the top.It is filled with 44.2 cm of water.If the speed of sound is 344 m/s, what willthe fundamental resonant frequency be

Answer 1

the fundamental resonant frequency is 95.76 Hz

Step-by-step explanation:

The computation of the fundamental resonant frequency be is given below:

= 1.34 m - 0.442 m

= 0.898 m

Now

`L = (\lambda)/(4) \\\\\lambda = 4L`

Now the fundamental resonant frequency is

`f = (V)/(\lambda) \\\\= (V)/(4L)\\\\= (344)/(4* 0.898)`

= 95.76 Hz

hence, the fundamental resonant frequency is 95.76 Hz