Question

If x= (4/5)^-2 divided by (1/4)^2,find the value of x^-1
can u plz telll the ans

Answer 1

`\displaystyle x^(-1)=(1)/(25)`

Explanation:

The value of x is given:

`\displaystyle x= ((4/5)^(-2))/((1/4)^2)`

We need to find:

`\displaystyle x^(-1)=(1)/(x)=((1)/(4)^2)/((4)/(5)^(-2))`

Operating:

`\displaystyle x^(-1)=(1)/(4)^2*(5)/(4)^(-2)`

Squaring:

`\displaystyle x^(-1)=(1)/(16)*(16)/(25)`

Multiplying:

`\mathbf{\displaystyle x^(-1)=(1)/(25)}`