for the first one it is the second option because of one property of logarithms:
log(a)-log(b)=log
![(a)/(b)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4csve9ghyam2nxyvna10u6d4e3rld2pfoh.png)
for the second one using the same property we can say that we third option is correct and not the second one but we use one more property of the logarithm
loga(b)^x=xloga(b) the power of the logarithm becomes a fator and
is equal to
![x^{(1)/(3)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/k5d1cjmmrb3y7yrc1440an06cli7cclsri.png)