Answer:
216

Explanation:
Given the figure.
And the perimeter in the ratio 4: 2: 1.
Perimeter of smallest circle =

To find:
Area of shaded region.
Solution:
To find the area, we need to have radius first.
And radius can be calculated by the given perimeter.
Formula for Perimeter is given as:
Perimeter =


Radius of smallest circle = 4 cm
Ratio of perimeter is equal to the ratio of the radii.
Radius of 2nd smallest circle by the given ratio = 8 cm
Radius of largest circle = 16 cm
Area of a circle is given the formula:

Area of the smallest circle =

Area of the 2nd smallest circle =

Area of the largest circle =

Area of the shaded region = Area of largest circle + 2
Area of 2nd smallest circle + 3
Area of smallest circle - 2
Area of smallest circle - 3
Area of 2nd smallest circle
Area of the shaded region = Area of largest circle - Area of 2nd smallest circle + Area of smallest circle =
