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F (x+y - 1) dx + (х + 2y -3)dy =0​
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F
(x+y - 1) dx + (х + 2y -3)dy =0​

User JaffaKetchup
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1 Answer

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Answer:

  1. We have dx and dy such that we take the derivative with respect to x and y ie dx/dy and dy/dx
  2. We treat y as a constant such that dx results in 1
  3. The dx results in 1
  4. The dy results in 2
  5. So 1+2 =3
User Badrobit
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